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A study on luminescence properties and energy transfer mechanism for NaCaY(PO4)2:Eu2+,Mn2+ phosphors for LED applications

Wei-Ren Liu and Pin-Chun Lin

Open Access Open Access

Abstract

A color-tunable NaCaY(PO4)2:Eu2+, Mn2+ was synthesized by a solid state reaction. NaCaY(PO4)2 crystallizes in the hexagonal structure system with space group of P6222 and Z = 1. The NaCaY(PO4)2:Eu2+ exhibits blue-greenish emission and broad excitation bands corresponding to the allowed f→d electronic transition of Eu2+. In addition, via the design of efficient energy transfer from Eu2+ to Mn2+, a high quality of white-emitting light could be generated in the optimized composition of NaCaY(PO4)2:1%Eu2+, 0.5%Mn2+ with CIE coordinates of (0.3389,0.3531) and CRI of 82, which is superior than that of blue chip and YAG phosphors. The results indicate that as-synthesized NaCaY(PO4)2:Eu2+, Mn2+ phosphors exhibits the potential to be an n-UV convertible phosphor.

© 2014 Optical Society of America

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Figures (6)
Fig. 1
Fig. 1 XRD patterns of KCaY(PO4)2 from JCPDS 51-1632 and as-synthesized NaCaY(PO4)2:1%Eu2+,10%Mn2+ sample. Inset: Crystal structure of NaCaY(PO4)2.

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Fig. 2
Fig. 2 (a) Excitation and emission spectra of as-synthesized NCYP:1%Eu2+ phosphor. (b) PL spectra of NCYP with different doping content of Eu2+. The inset shows PL intensity as a function of Eu2+ concentration.

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Fig. 3
Fig. 3 (a) Thermal stability test of as-synthesized NCYP:1%Eu2+ phosphor excited at 365 nm under different temperature. Inset: The comparison of NCYP and commodity; (b) CIE coordinates of NCYP:Eu as a function of temperature.

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Fig. 4
Fig. 4 PL spectra of NCYP:1%Eu2+, x%Mn2+ phosphors excited at 376 nm. Inset: energy transfer efficiency as a function of Mn2+ content.

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Fig. 5
Fig. 5 Dependence of Is0/Is of Eu2+ on (a) CMn6/3 and (b) CMn8/3.

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Fig. 6
Fig. 6 CIE diagrams of (a) NCYP:x%Eu2+ excited at 365 nm; (b) NCYP:1%Eu2+, y%Mn2+. Insets: the images of NCYP:1%Eu2+,y%Mn2+ phosphors excited at 365 nm in UV box.

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Equations (3)

Equations on this page are rendered with MathJax. Learn more.

Rc=2 [ 3V 4π x c Z ] 1/3
ln( I o I )=lnA− E a kT ,
I S 0 I S ∝ C α / 3
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